(-3x^2)+(278x)+(-325)=0

Solution for (-3x^2)+(278x)+(-325)=0 equation:

(-3x^2)+(278x)+(-325)=0

We add all the numbers together, and all the variables

(-3x^2)+278x-325=0

We get rid of parentheses

-3x^2+278x-325=0

a = -3; b = 278; c = -325;
Δ = b2-4ac
Δ = 2782-4·(-3)·(-325)
Δ = 73384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{73384}=\sqrt{4*18346}=\sqrt{4}*\sqrt{18346}=2\sqrt{18346}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(278)-2\sqrt{18346}}{2*-3}=\frac{-278-2\sqrt{18346}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(278)+2\sqrt{18346}}{2*-3}=\frac{-278+2\sqrt{18346}}{-6}
$